How to use the markdown.etree.SubElement function in Markdown

block = blocks.pop(0)
        m = self.RE.search(block)
        if m:
            before = block[:m.start()] # Lines before blockquote
            # Pass lines before blockquote in recursively for parsing forst.
            self.parser.parseBlocks(parent, [before])
            # Remove ``> `` from begining of each line.
            block = '\n'.join([self.clean(line) for line in 
                            block[m.start():].split('\n')])
        sibling = self.lastChild(parent)
        if sibling and sibling.tag == "blockquote":
            # Previous block was a blockquote so set that as this blocks parent
            quote = sibling
        else:
            # This is a new blockquote. Create a new parent element.
            quote = markdown.etree.SubElement(parent, 'blockquote')
        # Recursively parse block with blockquote as parent.
        self.parser.parseChunk(quote, block)

def handleMatch(self, m):
        tag1, tag2 = self.tag.split(",")
        el1 = markdown.etree.Element(tag1)
        el2 = markdown.etree.SubElement(el1, tag2)
        el2.text = m.group(3)
        return el1

def run(self, doc):
        div = etree.Element("div")
        div.attrib["class"] = "toc"
        last_li = None

        # Add title to the div
        if self.config["title"][0]:
            header = etree.SubElement(div, "span")
            header.attrib["class"] = "toctitle"
            header.text = self.config["title"][0]

        level = 0
        list_stack=[div]
        header_rgx = re.compile("[Hh][123456]")

        # Get a list of id attributes
        used_ids = []
        for c in doc.getiterator():
            if "id" in c.attrib:
                used_ids.append(c.attrib["id"])

        for (p, c) in self.iterparent(doc):
            if not c.text:
                continue

def _build_row(self, row, parent, align, border):
        """ Given a row of text, build table cells. """
        tr = etree.SubElement(parent, 'tr')
        tag = 'td'
        if parent.tag == 'thead':
            tag = 'th'
        cells = self._split_row(row, border)
        # We use align here rather than cells to ensure every row 
        # contains the same number of columns.
        for i, a in enumerate(align):
            c = etree.SubElement(tr, tag)
            try:
                c.text = cells[i].strip()
            except IndexError:
                c.text = ""
            if a:
                c.set('align', a)

def create_item(self, parent, block):
        """ Create a new li and parse the block with it as the parent. """
        li = markdown.etree.SubElement(parent, 'li')
        self.parser.parseBlocks(li, [block])

def run(self, parent, blocks):
        sibling = self.lastChild(parent)
        block = blocks.pop(0)
        theRest = ''
        if sibling and sibling.tag == "pre" and len(sibling) \
                    and sibling[0].tag == "code":
            # The previous block was a code block. As blank lines do not start
            # new code blocks, append this block to the previous, adding back
            # linebreaks removed from the split into a list.
            code = sibling[0]
            block, theRest = self.detab(block)
            code.text = markdown.AtomicString('%s\n%s\n' % (code.text, block.rstrip()))
        else:
            # This is a new codeblock. Create the elements and insert text.
            pre = markdown.etree.SubElement(parent, 'pre')
            code = markdown.etree.SubElement(pre, 'code')
            block, theRest = self.detab(block)
            code.text = markdown.AtomicString('%s\n' % block.rstrip())
        if theRest:
            # This block contained unindented line(s) after the first indented 
            # line. Insert these lines as the first block of the master blocks
            # list for future processing.
            blocks.insert(0, theRest)

channel = etree.SubElement(rss, "channel")

        for tag, text in (("title", self.ext.getConfig("TITLE")),
                          ("link", self.ext.getConfig("URL")),
                          ("description", None)):
            
            element = etree.SubElement(channel, tag)
            element.text = text

        for child in root:

            if child.tag in ["h1", "h2", "h3", "h4", "h5"]:
      
                heading = child.text.strip()
                item = etree.SubElement(channel, "item")
                link = etree.SubElement(item, "link")
                link.text = self.ext.getConfig("URL")
                title = etree.SubElement(item, "title")
                title.text = heading

                guid = ''.join([x for x in heading if x.isalnum()])
                guidElem = etree.SubElement(item, "guid")
                guidElem.text = guid
                guidElem.set("isPermaLink", "false")

            elif child.tag in ["p"]:
                try:
                    description = etree.SubElement(item, "description")
                except UnboundLocalError:
                    # Item not defined - moving on
                    pass

def _parse( self, parent, block ):
      method = {
        "name": None, 
        "params": []
      }
      
      for line in block:
        if line.startswith("=="):
          parent = self._parseHeader( parent, line )
          owner = parent
        
        elif line[0] not in ": \t":            
          if parent.get('class') == 'params':
            param = etree.SubElement(parent, 'div')
            param.set( 'class', 'param' )
            owner = param
          
          span = etree.SubElement(owner, 'span')
          span.set( 'class', 'name' )
          span.text = line.strip()
          
          if not method["name"]:
            method["name"] = span.text
            method["el"] = span
          else:
            method["params"].append(dict(name = span.text, required="true"))
          
        elif line[0] == ":":
          span = etree.SubElement(owner, 'span')
          span.set( 'class', 'description' )

def _build_row(self, row, parent, align, border):
        """ Given a row of text, build table cells. """
        tr = etree.SubElement(parent, 'tr')
        tag = 'td'
        if parent.tag == 'thead':
            tag = 'th'
        cells = self._split_row(row, border)
        # We use align here rather than cells to ensure every row 
        # contains the same number of columns.
        for i, a in enumerate(align):
            c = etree.SubElement(tr, tag)
            try:
                c.text = cells[i].strip()
            except IndexError:
                c.text = ""
            if a:
                c.set('align', a)