How to use the js-combinatorics.C function in js-combinatorics

To help you get started, we’ve selected a few js-combinatorics examples, based on popular ways it is used in public projects.

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github DefinitelyTyped / DefinitelyTyped / js-combinatorics / js-combinatorics-tests.ts View on Github external
import * as Combinatorics from "js-combinatorics";

const p:number = Combinatorics.P(1, 2);
const c:number = Combinatorics.C(1, 2);
const factorial:number = Combinatorics.factorial(5);
const factoradic:number[] = Combinatorics.factoradic(5);

const power = Combinatorics.power(["a", "b", "c"]);
const nextPower:string[] = power.next();
power.forEach((i:string[]) => console.log(i));
const powersLengths:number[] = power.map((i:string[]) => i.length);
const filteredPowers:string[][] = power.filter((i:string[]) => i.length > 0);
const allPowers:string[][] = power.toArray();
const powersCount = power.length;
const nthPower:string[] = power.nth(3);

const limitedCombination = Combinatorics.combination(["a", "b", "c"], 2);
const combination = Combinatorics.combination(["a", "b", "c"]);
const nextCombination:string[] = combination.next();
combination.forEach((i:string[]) => console.log(i));
github DefinitelyTyped / DefinitelyTyped / types / js-combinatorics / js-combinatorics-tests.ts View on Github external
import * as Combinatorics from "js-combinatorics";

const p:number = Combinatorics.P(1, 2);
const c:number = Combinatorics.C(1, 2);
const factorial:number = Combinatorics.factorial(5);
const factoradic:number[] = Combinatorics.factoradic(5);

const power = Combinatorics.power(["a", "b", "c"]);
const nextPower:string[] = power.next();
power.forEach((i:string[]) => console.log(i));
const powersLengths:number[] = power.map((i:string[]) => i.length);
const filteredPowers:string[][] = power.filter((i:string[]) => i.length > 0);
const allPowers:string[][] = power.toArray();
const powersCount = power.length;
const nthPower:string[] = power.nth(3);

const limitedCombination = Combinatorics.combination(["a", "b", "c"], 2);
const combination = Combinatorics.combination(["a", "b", "c"]);
const nextCombination:string[] = combination.next();
combination.forEach((i:string[]) => console.log(i));